Impure Math
Jan. 8th, 2005 02:02 pmT2 = 2xD / A
Where T is time in seconds, D is distance in metres and A is acceleration in metres per second. I want to calculate the number of days it takes to travel X number of Astronomical Units -- AU (or ua, if you actually listen to the Bureau International des Poids et Mesures) -- using Gs of acceleration.
T2 = 2xD / 10xAG
Thus:
T2= 2xDAUx150,000,000x1000 / 10xAG
And:
Td2 = 2xDAUx150,000,000x1000 / 10xAGx(24x60x60)2
Which is:
Td2 = 2xDAUx150,000,000x1000 / 10xAGx86,4002
Or:
Td2 = 2xDAUx150,000,000x1000 / AGx74,649,600,000
Which is close enough to:
Td2 = 2xDAUx2 / AG
Or
Td = 2xSQRT(DAU / AG)
So at a constant one G acceleration I can travel 100 AU in about 7 days? That seems off, somehow.
Now, thanks to
james_nicoll and
king_tirian, I've got it right.